Great effort. Thanks. Please look at Q 58. I don't believe it is correct. It should have been product of mode and median or something else...Mean is a very large number since sum of the series is 1 + 2*2 + 3*3*3 + 4*4*4*4 + .....+ 9*9*9*9*9*9*9*9*9
abt q 58: the sum is not quite large as there is formula to calculate it : [n(n+1)(2n+1)]/6 where n = 9!!! then divide by n(n+1)/2 again n is 9 this will giv u the mean !! den multiply by mode which is 9!! the answer is 57:)
4 comments:
Great effort. Thanks. Please look at Q 58. I don't believe it is correct. It should have been product of mode and median or something else...Mean is a very large number since sum of the series is 1 + 2*2 + 3*3*3 + 4*4*4*4 + .....+ 9*9*9*9*9*9*9*9*9
ven r the results goin to be out???
is it around may 25..plz reply soon
abt q 58:
the sum is not quite large as there is formula to calculate it :
[n(n+1)(2n+1)]/6
where n = 9!!!
then divide by n(n+1)/2
again n is 9
this will giv u the mean !! den multiply by mode which is 9!!
the answer is 57:)
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